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=3Z^2
We move all terms to the left:
-(3Z^2)=0
a = -3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-3)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$Z=\frac{-b}{2a}=\frac{0}{-6}=0$
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